Description
SQL Schema
The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
+----+-------+--------+-----------+
| Id | Name | Salary | ManagerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry | 80000 | 4 |
| 3 | Sam | 60000 | NULL |
| 4 | Max | 90000 | NULL |
+----+-------+--------+-----------+
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
+----------+
| Employee |
+----------+
| Joe |
+----------+
Solutions
1. join or direct
-- select e.name Employee
-- from Employee e join Employee m on e.ManagerId = m.Id
-- where e.Salary > m.Salary;
-- 14/14 cases passed (459 ms)
-- Your runtime beats 86.71 % of mysql submissions
-- Your memory usage beats 100 % of mysql submissions (0B)
select e.name Employee
from Employee e, Employee m
where e.ManagerId = m.Id and e.Salary > m.Salary;
-- 14/14 cases passed (1373 ms)
-- Your runtime beats 5 % of mysql submissions
-- Your memory usage beats 100 % of mysql submissions (0B)