Given two strings
text2, return the length of their longest common subsequence.
A subsequence of a string is a new string generated from the original string with some characters(can be none) deleted without changing the relative order of the remaining characters. (eg, “ace” is a subsequence of “abcde” while “aec” is not). A common subsequence of two strings is a subsequence that is common to both strings.
If there is no common subsequence, return 0.
Input: text1 = "abcde", text2 = "ace" Output: 3 Explanation: The longest common subsequence is "ace" and its length is 3.
Input: text1 = "abc", text2 = "abc" Output: 3 Explanation: The longest common subsequence is "abc" and its length is 3.
Input: text1 = "abc", text2 = "def" Output: 0 Explanation: There is no such common subsequence, so the result is 0.
1 <= text1.length <= 1000
1 <= text2.length <= 1000
- The input strings consist of lowercase English characters only.
# Time: O(mn) # Space: O(mn) class Solution: def longestCommonSubsequence(self, text1: str, text2: str) -> int: if not text1 or not text2: return 0 n1, n2 = len(text1), len(text2) dp = [[0 for _ in range(n2 + 1)] for _ in range(n1 + 1)] for i in range(1, n1 + 1): for j in range(1, n2 + 1): if text1[i - 1] == text2[j - 1]: dp[i][j] = dp[i - 1][j - 1] + 1 else: dp[i][j] = max(dp[i][j-1], dp[i-1][j]) return dp[n1][n2] # Runtime: 440 ms, faster than 60.67% # Memory Usage: 21.3 MB, less than 100.00%