Description
We are given the head node root
of a binary tree, where additionally every node’s value is either a 0 or a 1.
Return the same tree where every subtree (of the given tree) not containing a 1 has been removed.
(Recall that the subtree of a node X is X, plus every node that is a descendant of X.)
Example 1:
Input: [1,null,0,0,1]
Output: [1,null,0,null,1]
Explanation:
Only the red nodes satisfy the property "every subtree not containing a 1".
The diagram on the right represents the answer.
Example 2:
Input: [1,0,1,0,0,0,1]
Output: [1,null,1,null,1]
Example 3:
Input: [1,1,0,1,1,0,1,0]
Output: [1,1,0,1,1,null,1]
Note:
- The binary tree will have at most
100 nodes
. - The value of each node will only be
0
or1
.
Solutions
1. Recursion
# Time: O(logn)
# Space: O(1)
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def pruneTree(self, root: TreeNode) -> TreeNode:
if not root:
return None
if root.left:
root.left = self.pruneTree(root.left)
if root.right:
root.right = self.pruneTree(root.right)
if not root.left and not root.right and root.val == 0:
return None
return root
# 28/28 cases passed (28 ms)
# Your runtime beats 71.93 % of python3 submissions
# Your memory usage beats 100 % of python3 submissions (12.6 MB)